164
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Number
$164$ (
one hundred and sixty-four
) is:
$2^2 \times 41$
The $5$th positive integer solution after $1, 3, 15, 104$ to $\map \phi n = \map \phi {n + 1}$:
$\map \phi {164} = 80 = \map \phi {165}$
Also see
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Consecutive Integers with Same Euler Phi Value