536,870,912

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Number

$536 \, 870 \, 912$ (five hundred and thirty-six million, eight hundred and seventy thousand, nine hundred and twelve) is:

$2^{29}$


The $29$th power of $2$:
$536 \, 870 \, 912 = 2^{29}$


The $30$th almost perfect number:
$\map {\sigma_1} {536 \, 870 \, 912} = 1 \, 073 \, 741 \, 823 = 2 \times 536 \, 870 \, 912 - 1$


Of particular interest, as it is almost pandigital: only $4$ is missing.


Also see

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