Biconditional is Reflexive/Proof 1

Theorem

$\vdash p \iff p$


Proof

By the tableau method of natural deduction:

$\vdash p \iff p$
Line Pool Formula Rule Depends upon Notes
1 $p \implies p$ Theorem Introduction (None) Law of Identity: Formulation 2
2 $p \iff p$ Biconditional Introduction: $\iff \II$ 1, 1

$\blacksquare$

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