Biconditional is Transitive

Theorem

The biconditional operator is transitive:


Formulation 1

$p \iff q, q \iff r \vdash p \iff r$


Formulation 2

$\vdash \paren {\paren {p \iff q} \land \paren {q \iff r} } \implies \paren {p \iff r}$
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