Brocard's Problem

Unsolved Problem

For which pairs of (strictly) positive integers $\tuple {m, n}$ do the following hold:

$n! + 1 = m^2$

The only known pairs are:

\(\text {(1)}: \quad\) \(\, \ds \tuple {5, 4}: \, \) \(\ds 4! + 1\) \(=\) \(\ds 24 + 1 = 25 = 5^2\)
\(\text {(2)}: \quad\) \(\, \ds \tuple {11, 5}: \, \) \(\ds 5! + 1\) \(=\) \(\ds 120 + 1 = 121 = 11^2\)
\(\text {(3)}: \quad\) \(\, \ds \tuple {71, 7}: \, \) \(\ds 7! + 1\) \(=\) \(\ds 5040 + 1 = 5041 = 71^2\)


Also see

  • Definition:Brown Numbers


Source of Name

This entry was named for Pierre René Jean Baptiste Henri Brocard.


Sources

  • 1980: David M. Burton: Elementary Number Theory (revised ed.) ... (previous) ... (next): Chapter $1$: Some Preliminary Considerations: $1.1$ Mathematical Induction: Problems $1.1$: $5 \ \text {(a)}$
  • 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $4$
  • 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $7$
  • 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $121$
  • 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $4$
  • 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $7$
  • 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $121$