Cantor Space is Complete Metric Space

Theorem

Let $T = \struct {\CC, \tau_d}$ be the Cantor space.


Then $T$ is a complete metric space.


Proof

We have that the Cantor space is a metric subspace of the real number space $\R$, and hence a metric space.

We also have Cantor Space is Compact.

The result follows from Compact Metric Space is Complete.

$\blacksquare$


Sources

  • 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text {II}$: Counterexamples: $29$. The Cantor Set: $2$
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