Class Mapping has Minimally Superinductive Class

Theorem

Let $g$ be a (class) mapping.

Then there exists a class $M$ that is minimally superinductive under $g$.


Proof


This theorem requires a proof.
In particular: According to the rubric of the exercise, this is to be proved using one of the versions of the Transfinite Recursion Theorem that appears in S&F
You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof.
To discuss this page in more detail, feel free to use the talk page.
When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.
If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page.



Sources

  • 2010: Raymond M. Smullyan and Melvin Fitting: Set Theory and the Continuum Problem (revised ed.) ... (previous) ... (next): Chapter $6$: Order Isomorphism and Transfinite Recursion: $\S 5$ Transfinite recursion theorems: Exercise $5.2$