Closed Form for Centered Hexagonal Numbers
Theorem
Let $C_n$ be the $n$th centered hexagonal number.
Then:
- $C_n = 3 n \paren {n - 1} + 1$
Proof
By the definition of centered hexagonal number:
| \(\ds C_n\) | \(=\) | \(\ds 1 + \sum_{k \mathop = 1}^{n - 1} 6 k\) | Definition of Centered Hexagonal Number | |||||||||||
| \(\ds \) | \(=\) | \(\ds 1 + 6 \sum_{k \mathop = 1}^{n - 1} k\) | ||||||||||||
| \(\ds \) | \(=\) | \(\ds 6 \paren {\dfrac {n \paren {n - 1} } 2} + 1\) | Closed Form for Triangular Numbers | |||||||||||
| \(\ds \) | \(=\) | \(\ds 3 n \paren {n - 1} + 1\) |
$\blacksquare$