Derivative of Sine Function/Proof 3
Theorem
- $\map {\dfrac \d {\d x} } {\sin x} = \cos x$
Proof
| \(\ds \dfrac \d {\d x} \sin x\) | \(=\) | \(\ds \dfrac \d {\d x} \map \cos {\frac \pi 2 - x}\) | Cosine of Complement equals Sine | |||||||||||
| \(\ds \) | \(=\) | \(\ds \map \sin {\frac \pi 2 - x}\) | Derivative of Cosine Function and Chain Rule for Derivatives | |||||||||||
| \(\ds \) | \(=\) | \(\ds \cos x\) | Sine of Complement equals Cosine |
$\blacksquare$