Difference of Logarithms/Proof 3

Theorem

$\log_b x - \log_b y = \map {\log_b} {\dfrac x y}$


Proof

\(\ds \map {\log_b} {\frac x y} + \log_b y\) \(=\) \(\ds \map {\log_b} {\frac x y \times y}\) Sum of Logarithms
\(\ds \) \(=\) \(\ds \log_b x\)
\(\ds \leadsto \ \ \) \(\ds \map {\log_b} {\frac x y}\) \(=\) \(\ds \log_b x - \log_b y\) subtracting $\log_b y$ from both sides

$\blacksquare$


Sources

  • 1997: Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms (3rd ed.) ... (previous) ... (next): $\S 1.2.2$: Numbers, Powers, and Logarithms: Exercise $15$