Differentiable Function is Continuous

Theorem

Let $f$ be a real function defined on an interval $I$.

Let $x_0 \in I$ such that $f$ is differentiable at $x_0$.


Then $f$ is continuous at $x_0$.


Corollary

If $f$ is not continuous at $x_0$, $f$ is not differentiable at $x_0$.


Proof

We have by hypothesis that $\map {f'} {x_0}$ exists.

Let $x, x_0 \in I$ such that $x \ne x_0$. Then:

\(\ds \map f x - \map f {x_0}\) \(=\) \(\ds \frac {\map f x - \map f {x_0} } {x - x_0} \cdot \paren {x - x_0}\)
\(\ds \) \(\to\) \(\ds \map {f'} {x_0} \cdot 0\) as $x \to x_0$


Thus:

$\map f x \to \map f {x_0}$ as $x \to x_0$

or in other words:

$\ds \lim_{x \mathop \to x_0} \map f x = \map f {x_0}$


The result follows by definition of continuous.

$\blacksquare$


Also see


Sources

  • 1977: K.G. Binmore: Mathematical Analysis: A Straightforward Approach ... (previous) ... (next): $\S 10.6$
  • 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): continuous function (continuous mapping)
  • 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): differentiable
  • 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): continuous function (continuous mapping, continuous map)
  • 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): differentiable