Equivalence of Definitions of Field (Abstract Algebra)
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Theorem
The following definitions of the concept of Field (Abstract Algebra) are equivalent:
Definition $1$
$\struct {F, +, \times}$ is a field if and only if:
- $(1): \quad$ the algebraic structure $\struct {F, +}$ is an abelian group
- $(2): \quad$ the algebraic structure $\struct {F^*, \times}$ is an abelian group where $F^* = F \setminus \set {0_F}$
- $(3): \quad$ the operation $\times$ distributes over $+$.
Definition $2$
Let $\struct {F, +, \times}$ be an integral domain such that every non-zero element $a$ of $F$ has a multiplicative inverse $a^{-1}$ such that:
- $a \times a^{-1} = 1_F = a^{-1} \times a$
where $1_F$ denotes the unity of $\struct {F, +, \times}$.
Then $\struct {F, +, \times}$ is a field.
Definition $3$
Let $\struct {F, +, \times}$ be a commutative ring with unity $\struct {F, +, \times}$ such that every non-zero element $a$ of $F$ has a multiplicative inverse:
- $a^{-1}$ such that $a \times a^{-1} = 1_F = a^{-1} \times a$
where $1_F$ denotes the unity of $\struct {F, +, \times}$.
Then $\struct {F, +, \times}$ is a field.
Definition $4$
Let $\struct {F, +, \times}$ be a non-trivial division ring whose ring product is commutative.
Then $\struct {F, +, \times}$ is a field.
Definition $5$
$\struct {F, +, \times}$ is a field if and only if it fulfils the conditions of the field axioms, as follows:
| \((\text A 0)\) | $:$ | Closure under addition | \(\ds \forall x, y \in F:\) | \(\ds x + y \in F \) | |||||
| \((\text A 1)\) | $:$ | Associativity of addition | \(\ds \forall x, y, z \in F:\) | \(\ds \paren {x + y} + z = x + \paren {y + z} \) | |||||
| \((\text A 2)\) | $:$ | Commutativity of addition | \(\ds \forall x, y \in F:\) | \(\ds x + y = y + x \) | |||||
| \((\text A 3)\) | $:$ | Identity element for addition | \(\ds \exists 0_F \in F: \forall x \in F:\) | \(\ds x + 0_F = x = 0_F + x \) | $0_F$ is called the zero | ||||
| \((\text A 4)\) | $:$ | Inverse elements for addition | \(\ds \forall x \in F: \exists x' \in F:\) | \(\ds x + x' = 0_F = x' + x \) | $x'$ is called a negative element | ||||
| \((\text M 0)\) | $:$ | Closure under product | \(\ds \forall x, y \in F:\) | \(\ds x \times y \in F \) | |||||
| \((\text M 1)\) | $:$ | Associativity of product | \(\ds \forall x, y, z \in F:\) | \(\ds \paren {x \times y} \times z = x \times \paren {y \times z} \) | |||||
| \((\text M 2)\) | $:$ | Commutativity of product | \(\ds \forall x, y \in F:\) | \(\ds x \times y = y \times x \) | |||||
| \((\text M 3)\) | $:$ | Identity element for product | \(\ds \exists 1_F \in F, 1_F \ne 0_F: \forall x \in F:\) | \(\ds x \times 1_F = x = 1_F \times x \) | $1_F$ is called the unity | ||||
| \((\text M 4)\) | $:$ | Inverse elements for product | \(\ds \forall x \in F^*: \exists x^{-1} \in F^*:\) | \(\ds x \times x^{-1} = 1_F = x^{-1} \times x \) | |||||
| \((\text D)\) | $:$ | Product is distributive over addition | \(\ds \forall x, y, z \in F:\) | \(\ds x \times \paren {y + z} = \paren {x \times y} + \paren {x \times z} \) |
These are called the field axioms.
Proof
Definition $(1)$ implies Definition $(5)$
Let $\struct {F, +, \times}$ be a field by definition $1$.
Recall definition $1$ of Field (Abstract Algebra):
$\struct {F, +, \times}$ is a field if and only if:
- $(1): \quad$ the algebraic structure $\struct {F, +}$ is an abelian group
- $(2): \quad$ the algebraic structure $\struct {F^*, \times}$ is an abelian group where $F^* = F \setminus \set {0_F}$
- $(3): \quad$ the operation $\times$ distributes over $+$.
By the definition of abelian group:
- $(\text A 0): \quad \struct {F, +}$ is closed
- $(\text A 1): \quad +$ is associative on $F$
- $(\text A 2): \quad +$ is commutative on $F$
- $(\text A 3): \quad$ there exists an identity element $0_F$ for $+$
- $(\text A 4): \quad$ for every $a \in F$ there exists an inverse element $-a$ for $+$
Then:
- $(\text M 0): \quad \struct {F, \times}$ is closed under addition
- $(\text M 1): \quad \times$ is associative on $F$
- $(\text M 2): \quad \times$ is commutative on $F$
- $(\text M 3): \quad$ there exists an identity element $1_F$ for $\times$
- $(\text M 4): \quad$ for every $a \in F$ there exists an inverse element $a^{-1}$ for $\times$
Finally we are given:
- $(\text D): \quad \times$ is distributive over $+$ in $\struct {F, +, \times}$.
Thus $\struct {F, +, \times}$ is a field by definition $5$.
$\Box$
Definition $(5)$ implies Definition $(1)$
Let $\struct {F, +, \times}$ be a field by definition $5$.
Recall definition $5$ of Field (Abstract Algebra):
$\struct {F, +, \times}$ is a field if and only if it fulfils the conditions of the field axioms, as follows:
| \((\text A 0)\) | $:$ | Closure under addition | \(\ds \forall x, y \in F:\) | \(\ds x + y \in F \) | |||||
| \((\text A 1)\) | $:$ | Associativity of addition | \(\ds \forall x, y, z \in F:\) | \(\ds \paren {x + y} + z = x + \paren {y + z} \) | |||||
| \((\text A 2)\) | $:$ | Commutativity of addition | \(\ds \forall x, y \in F:\) | \(\ds x + y = y + x \) | |||||
| \((\text A 3)\) | $:$ | Identity element for addition | \(\ds \exists 0_F \in F: \forall x \in F:\) | \(\ds x + 0_F = x = 0_F + x \) | $0_F$ is called the zero | ||||
| \((\text A 4)\) | $:$ | Inverse elements for addition | \(\ds \forall x \in F: \exists x' \in F:\) | \(\ds x + x' = 0_F = x' + x \) | $x'$ is called a negative element | ||||
| \((\text M 0)\) | $:$ | Closure under product | \(\ds \forall x, y \in F:\) | \(\ds x \times y \in F \) | |||||
| \((\text M 1)\) | $:$ | Associativity of product | \(\ds \forall x, y, z \in F:\) | \(\ds \paren {x \times y} \times z = x \times \paren {y \times z} \) | |||||
| \((\text M 2)\) | $:$ | Commutativity of product | \(\ds \forall x, y \in F:\) | \(\ds x \times y = y \times x \) | |||||
| \((\text M 3)\) | $:$ | Identity element for product | \(\ds \exists 1_F \in F, 1_F \ne 0_F: \forall x \in F:\) | \(\ds x \times 1_F = x = 1_F \times x \) | $1_F$ is called the unity | ||||
| \((\text M 4)\) | $:$ | Inverse elements for product | \(\ds \forall x \in F^*: \exists x^{-1} \in F^*:\) | \(\ds x \times x^{-1} = 1_F = x^{-1} \times x \) | |||||
| \((\text D)\) | $:$ | Product is distributive over addition | \(\ds \forall x, y, z \in F:\) | \(\ds x \times \paren {y + z} = \paren {x \times y} + \paren {x \times z} \) |
These are called the field axioms.
From $(\text A 0)$ to $(\text A 4)$, $\struct {F, +}$ is an abelian group.
From $(\text M 0)$ to $(\text M 4)$, $\struct {F \setminus \set 0_F, \times}$ is an abelian group.
Finally from $D$, $\times$ is distributive over $+$.
Thus $\struct {F, +, \times}$ is a field by definition $1$.
$\Box$
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