Equivalence of Definitions of Perfectly Inelastic Collision
Theorem
The following definitions of the concept of Perfectly Inelastic Collision are equivalent:
Definition $1$
A perfectly inelastic collision is a collision in which the coefficient of restitution is equal to zero.
Definition $2$
A perfectly inelastic collision is a collision after which the bodies involved remain in contact with each other and move as one body.
Proof
Recall the definition of Coefficient of Restitution:
Let two solid bodies $B_1$ and $B_2$ be in collision.
Let the components of the relative velocities of $B_1$ and $B_2$ in the direction of their common normal be respectively:
- $\mathbf u_1$ and $\mathbf u_2$ before the collision
- $\mathbf v_1$ and $\mathbf v_2$ after the collision.
By Newton's Law of Restitution:
- $\mathbf v_2 - \mathbf v_1 = -e \paren {\mathbf u_2 - \mathbf u_1}$
The coefficient $e$ is known as the coefficient of restitution.
Let $\CC$ be a perfectly inelastic collision by definition $1$.
Recall definition $1$ of Perfectly Inelastic Collision:
A perfectly inelastic collision is a collision in which the coefficient of restitution is equal to zero.
We have:
- $\mathbf v_2 - \mathbf v_1 = -0 \times \paren {\mathbf u_2 - \mathbf u_1}$
That is:
- $\mathbf v_2 - \mathbf v_1 = 0$
In other words:
- $\mathbf v_2 = \mathbf v_1$
That is, $B_1$ and $B_2$ move with the same velocity, and as they have just collided, they are still in contact.
Thus $\CC$ is a perfectly inelastic collision by definition $2$.
$\Box$
Definition $(2)$ implies Definition $(1)$
Let $\CC$ be a perfectly inelastic collision by definition $2$.
Recall definition $2$ of Perfectly Inelastic Collision:
A perfectly inelastic collision is a collision after which the bodies involved remain in contact with each other and move as one body.
Then by definition:
- $\mathbf v_2 = \mathbf v_1$
That is:
- $\mathbf v_2 - \mathbf v_1 = 0$
We have:
- $\mathbf v_2 - \mathbf v_1 = -e \times \paren {\mathbf u_2 - \mathbf u_1}$
But as $B_1$ and $B_2$ have just collided, it means that their initial velocities must have been unequal.
That is:
- $\mathbf u_2 \ne \mathbf u_1$
That is:
- $\mathbf u_2 - \mathbf u_1 \ne 0$
So for $-e \times \paren {\mathbf u_2 - \mathbf u_1} = 0$, it is necessary that $e = 0$.
Thus $\CC$ is a perfectly inelastic collision by definition $1$.
$\blacksquare$
Sources
- 2014: Christopher Clapham and James Nicholson: The Concise Oxford Dictionary of Mathematics (5th ed.) ... (previous) ... (next): coefficient of restitution
- 2021: Richard Earl and James Nicholson: The Concise Oxford Dictionary of Mathematics (6th ed.) ... (previous) ... (next): coefficient of restitution