Exponential of Zero/Proof 4

Theorem

$\exp 0 = 1$


Proof

This proof assumes the Definition of $\exp x$ as the unique continuous extension of $e^x$.

\(\ds \exp 0\) \(=\) \(\ds e^0\)
\(\ds \) \(=\) \(\ds 1\) Definition of $x^0$, where $x \ne 0$

$\blacksquare$

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