Hyperbolic Secant Function is Even/Proof 1

Theorem

$\map \sech {-x} = \sech x$


Proof

\(\ds \map \sech {-x}\) \(=\) \(\ds \frac 1 {\map \cosh {-x} }\) Definition 2 of Hyperbolic Secant
\(\ds \) \(=\) \(\ds \frac 1 {\cosh x}\) Hyperbolic Cosine Function is Even
\(\ds \) \(=\) \(\ds \sech x\)

$\blacksquare$

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