Intersection Absorbs Union/Proof 1

Theorem

$S \cap \paren {S \cup T} = S$


Proof

\(\ds \) \(\) \(\ds S \subseteq \paren {S \cup T}\) Set is Subset of Union
\(\ds \) \(\leadsto\) \(\ds S \cap \paren {S \cup T} = S\) Intersection with Subset is Subset‎

$\blacksquare$