Inverse of Reflexive Relation is Reflexive

Theorem

Let $\RR$ be a relation on a set $S$.


If $\RR$ is reflexive, then so is $\RR^{-1}$.


Proof

\(\ds x\) \(\in\) \(\ds S\)
\(\ds \leadsto \ \ \) \(\ds \tuple {x, x}\) \(\in\) \(\ds \RR\) Definition of Reflexive Relation
\(\ds \leadsto \ \ \) \(\ds \tuple {x, x}\) \(\in\) \(\ds \RR^{-1}\) Definition of Inverse Relation

Hence the result by definition of reflexive relation.

$\blacksquare$


Sources

  • 1971: Robert H. Kasriel: Undergraduate Topology ... (previous) ... (next): $\S 1.19$: Some Important Properties of Relations: Exercise $9$