Locally Compact Space is Weakly Locally Compact
Theorem
Let $T = \struct{S, \tau}$ be a locally compact topological space.
Then $T$ is weakly locally compact.
Proof
We are given $T$ is locally compact, so every point of $S$ has a neighborhood basis consisting of compact sets.
Let $x \in S$ be arbitrary.
From Space is Neighborhood of all its Points, $S$ is a neighborhood of $x$ in $S$.
So, every point contained in $S$ has a compact neighborhood.
Hence, $T$ is weakly locally compact.
$\blacksquare$