Modus Tollendo Tollens/Sequent Form/Proof 1

Theorem

The Modus Tollendo Tollens can be symbolised by the sequent:

\(\ds p\) \(\implies\) \(\ds q\)
\(\ds \neg q\) \(\) \(\ds \)
\(\ds \vdash \ \ \) \(\ds \neg p\) \(\) \(\ds \)


Proof

By the tableau method of natural deduction:

$p \implies q, \neg q \vdash \neg p$
Line Pool Formula Rule Depends upon Notes
1 1 $p \implies q$ Premise (None)
2 2 $\neg q$ Premise (None)
3 1, 2 $\neg p$ Modus Tollendo Tollens (MTT) 1, 2

$\blacksquare$


Sources

  • 1965: E.J. Lemmon: Beginning Logic ... (previous) ... (next): Chapter $1$: The Propositional Calculus $1$: $2$ Conditionals and Negation: Theorem $5$