Potential Energy of Position

Physical Law

Let $B$ be a body of mass $m$ in a gravitational field.

Let the Acceleration Due to Gravity be of constant magnitude $g$.

Let $B$ be at a height $h$ above a reference level $h_0$.


Then the potential energy $P$ of $B$ due to the position of $B$ relative to $h_0$ is given by:

$P = m g h$


Proof


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Sources

  • 1972: George F. Simmons: Differential Equations ... (previous) ... (next): $1$: The Nature of Differential Equations: $\S 5$: Falling Bodies and Other Rate Problems
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