Product of Reciprocals of Real Numbers

Theorem

$\forall x, y \in \R_{\ne 0}: \dfrac 1 x \times \dfrac 1 y = \dfrac 1 {x \times y}$


Proof

\(\ds \frac 1 {x \times y} \times \paren {x \times y}\) \(=\) \(\ds 1\) Real Number Axiom $\R \text M4$: Inverses for Multiplication
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y} \times \paren {x \times y} \times \frac 1 y\) \(=\) \(\ds 1 \times \frac 1 y\) as $y \ne 0$
\(\ds \leadsto \ \ \) \(\ds \paren {\frac 1 {x \times y} \times x} \times \paren {y \times \frac 1 y}\) \(=\) \(\ds 1 \times \frac 1 y\) Real Number Axiom $\R \text M1$: Associativity of Multiplication
\(\ds \leadsto \ \ \) \(\ds \paren {\frac 1 {x \times y} \times x} \times 1\) \(=\) \(\ds 1 \times \frac 1 y\) Real Number Axiom $\R \text M4$: Inverses for Multiplication
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y} \times x\) \(=\) \(\ds \frac 1 y\) Real Number Axiom $\R \text M3$: Identity Element for Multiplication
\(\ds \leadsto \ \ \) \(\ds \paren {\frac 1 {x \times y} \times x} \times \frac 1 x\) \(=\) \(\ds \frac 1 y \times \frac 1 x\) as $x \ne 0$
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y} \times \paren {x \times \frac 1 x}\) \(=\) \(\ds \frac 1 y \times \frac 1 x\) Real Number Axiom $\R \text M1$: Associativity of Multiplication
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y} \times 1\) \(=\) \(\ds \frac 1 y \times \frac 1 x\) Real Number Axiom $\R \text M4$: Inverses for Multiplication
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y}\) \(=\) \(\ds \frac 1 y \times \frac 1 x\) Real Number Axiom $\R \text M3$: Identity Element for Multiplication
\(\ds \leadsto \ \ \) \(\ds \frac 1 {x \times y}\) \(=\) \(\ds \frac 1 x \times \frac 1 y\) Real Number Axiom $\R \text M2$: Commutativity of Multiplication

$\blacksquare$


Sources

  • 2000: James R. Munkres: Topology (2nd ed.) ... (previous) ... (next): $1$: Set Theory and Logic: $\S 4$: The Integers and the Real Numbers: Exercise $1 \ \text{(m)}$