Real Function with Positive Derivative is Increasing

Theorem

Let $f$ be a real function which is continuous on the closed interval $\closedint a b$ and differentiable on the open interval $\openint a b$.


Let:

$\forall x \in \openint a b: \map {f'} x \ge 0$

Then $f$ is increasing on $\closedint a b$.


Proof

Let $c, d \in \closedint a b$ such that $c < d$.

Then $f$ satisfies the conditions of the Mean Value Theorem on $\closedint c d$.

Hence:

$\exists \xi \in \openint c d: \map {f'} \xi = \dfrac {\map f d - \map f c} {d - c}$


Let $f$ be such that:

$\forall x \in \openint a b: \map {f'} x \ge 0$

Then:

$\map {f'} \xi \ge 0$

and hence:

$\map f d \ge \map f c$

Thus $f$ is increasing on $\closedint a b$.

$\blacksquare$


Sources

  • 1977: K.G. Binmore: Mathematical Analysis: A Straightforward Approach ... (previous) ... (next): $\S 12.7 \ \text {(i)}$
  • 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): monotonic increasing function
  • 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): monotonic increasing function