Set Difference is Subset

Theorem

Set difference is a subset of the first set:

$S \setminus T \subseteq S$


Proof 1

\(\ds x \in S \setminus T\) \(\leadsto\) \(\ds x \in S \land x \notin T\) Definition of Set Difference
\(\ds \) \(\leadsto\) \(\ds x \in S\) Rule of Simplification

The result follows from the definition of subset.

$\blacksquare$


Proof 2

\(\ds S \setminus T\) \(=\) \(\ds S \cap \complement_S \left({T}\right)\) Set Difference as Intersection with Relative Complement
\(\ds \) \(\subseteq\) \(\ds S\) Intersection is Subset

$\blacksquare$


Sources

  • 1971: Allan Clark: Elements of Abstract Algebra ... (previous) ... (next): Chapter $1$: The Notation and Terminology of Set Theory: $\S 8$
  • 1993: Keith Devlin: The Joy of Sets: Fundamentals of Contemporary Set Theory (2nd ed.) ... (previous) ... (next): $\S 1$: Naive Set Theory: $\S 1.2$: Operations on Sets