Sine of 60 Degrees

Theorem

$\sin 60 \degrees = \sin \dfrac \pi 3 = \dfrac {\sqrt 3} 2$

where $\sin$ denotes the sine function.


Proof

\(\ds \sin 60 \degrees\) \(=\) \(\ds \map \cos {90 \degrees - 60 \degrees}\) Cosine of Complement equals Sine
\(\ds \) \(=\) \(\ds \cos 30 \degrees\)
\(\ds \) \(=\) \(\ds \dfrac {\sqrt 3} 2\) Cosine of $30 \degrees$

$\blacksquare$


Sources

  • 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text V$. Trigonometry: Special angles
  • 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 5$: Trigonometric Functions: Exact Values for Trigonometric Functions of Various Angles
  • 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): trigonometric function
  • 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): trigonometric function
  • 2014: Christopher Clapham and James Nicholson: The Concise Oxford Dictionary of Mathematics (5th ed.) ... (previous) ... (next): Appendix $12$: Trigonometric formulae: Trigonometric values for some special angles
  • 2021: Richard Earl and James Nicholson: The Concise Oxford Dictionary of Mathematics (6th ed.) ... (previous) ... (next): Appendix $14$: Trigonometric formulae: Trigonometric values for some special angles