Smallest Pythagorean Quadrilateral with Integer Sides

Theorem

The smallest Pythagorean quadrilateral in which the sides of the $4$ right triangles formed by its sides and perpendicular diagonals are all integers has an area of $21 \, 576$.

The sides of the right triangles in question are:

$25, 60, 65$
$91, 60, 109$
$91, 312, 325$
$25, 312, 313$


Proof

The $4$ right triangles are inspected:

\(\ds 25^2 + 60^2\) \(=\) \(\ds 625 + 3600\)
\(\ds \) \(=\) \(\ds 4225\)
\(\ds \) \(=\) \(\ds 65^2\)


\(\ds 91^2 + 60^2\) \(=\) \(\ds 8281 + 3600\)
\(\ds \) \(=\) \(\ds 11 \, 881\)
\(\ds \) \(=\) \(\ds 109^2\)


\(\ds 91^2 + 312^2\) \(=\) \(\ds 8281 + 97 \, 344\)
\(\ds \) \(=\) \(\ds 105 \, 625\)
\(\ds \) \(=\) \(\ds 325^2\)


\(\ds 25^2 + 312^2\) \(=\) \(\ds 625 + 97 \, 344\)
\(\ds \) \(=\) \(\ds 97 \, 969\)
\(\ds \) \(=\) \(\ds 313^2\)


The area of each right triangle is calculated:

\(\ds \dfrac {25 \times 60} 2\) \(=\) \(\ds 750\)
\(\ds \dfrac {91 \times 60} 2\) \(=\) \(\ds 2730\)
\(\ds \dfrac {91 \times 312} 2\) \(=\) \(\ds 14 \, 196\)
\(\ds \dfrac {25 \times 312} 2\) \(=\) \(\ds 3900\)

Thus the total area is:

$750 + 2730 + 14 \, 196 + 3900 = 21 \, 576$


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Historical Note

David Wells reports in his Curious and Interesting Numbers, 2nd ed. of $1997$ that this result was published in Journal of Recreational Mathematics Volume $21$ no. $9$ by Hugh ApSimon, but this has not been corroborated.

It is also uncertain at this stage exactly what a Pythagorean quadrilateral actually is.


Sources

  • 1989: Andy Pepperdine: Pythagorean Quadrilaterals (J. Recr. Math. Vol. 21: pp. 8 – 12)
  • 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $21,576$