Subgroup is Normal iff Contains Conjugate Elements

Theorem

Let $\struct {G, \circ}$ be a group whose identity is $e$.

Let $N$ be a subgroup of $G$.


Then $N$ is normal in $G$ if and only if:

\(\text {(1)}: \quad\) \(\ds \forall g \in G: \, \) \(\ds n \in N\) \(\iff\) \(\ds g \circ n \circ g^{-1} \in N\)
\(\text {(2)}: \quad\) \(\ds \forall g \in G: \, \) \(\ds n \in N\) \(\iff\) \(\ds g^{-1} \circ n \circ g \in N\)


Proof

By definition, a subgroup is normal in $G$ if and only if:

$\forall g \in G: g \circ N = N \circ g$


Necessary Condition

Suppose that $g \circ N = N \circ g$, by definition 1 of normality in $G$.

Let $n \in N$.

Then:

\(\ds g \circ n\) \(\in\) \(\ds N \circ g\) Definition of Coset
\(\ds \leadstoandfrom \ \ \) \(\ds \exists n_1 \in N: \, \) \(\ds g \circ n\) \(=\) \(\ds n_1 \circ g\) Definition of Coset
\(\ds \leadstoandfrom \ \ \) \(\ds g \circ n \circ g^{-1}\) \(=\) \(\ds n_1\) Division Laws for Groups
\(\ds \leadstoandfrom \ \ \) \(\ds g \circ n \circ g^{-1}\) \(\in\) \(\ds N\) Definition of $n_1$

$\Box$


Sufficient Condition

Suppose that:

$\forall g \in G: \paren {n \in N \iff g \circ n \circ g^{-1} \in N}$

Let $g \circ n \circ g^{-1} \in N$.

\(\ds \exists n_1 \in N: \, \) \(\ds g \circ n \circ g^{-1}\) \(=\) \(\ds n_1\)
\(\ds \leadsto \ \ \) \(\ds g \circ n\) \(=\) \(\ds n_1 \circ g\) Division Laws for Groups
\(\ds \leadsto \ \ \) \(\ds g \circ n\) \(\in\) \(\ds N \circ g\) Definition of Coset
\(\ds \leadsto \ \ \) \(\ds g \circ N\) \(\subseteq\) \(\ds N \circ g\) Definition of Subset


Similarly:

\(\ds \exists n_2 \in N: \, \) \(\ds g \circ n \circ g^{-1}\) \(=\) \(\ds n_2\)
\(\ds \leadsto \ \ \) \(\ds n \circ g^{-1}\) \(=\) \(\ds g^{-1} \circ n_2\) Division Laws for Groups
\(\ds \leadsto \ \ \) \(\ds n \circ g^{-1}\) \(\in\) \(\ds g^{-1} \circ N\) Definition of Coset
\(\ds \leadsto \ \ \) \(\ds N \circ g^{-1}\) \(\subseteq\) \(\ds g^{-1} \circ N\) Definition of Subset

As $g$ is arbitrary, then so is $g^{-1}$.

Thus:

$N \circ g \subseteq g \circ N$

By definition of set equality:

$g \circ N = N \circ g$


Also see


Sources

  • 1965: J.A. Green: Sets and Groups ... (previous) ... (next): $\S 6.6$. Normal subgroups
  • 1966: Richard A. Dean: Elements of Abstract Algebra ... (previous) ... (next): $\S 1.10$: Theorem $26$
  • 1967: George McCarty: Topology: An Introduction with Application to Topological Groups ... (previous) ... (next): $\text{II}$: Morphisms
  • 1978: Thomas A. Whitelaw: An Introduction to Abstract Algebra ... (previous) ... (next): $\S 49.3$ Normal subgroups
  • 1996: John F. Humphreys: A Course in Group Theory ... (previous) ... (next): $\S 7$: Definition $7.3$