Subgroup of Abelian Group is Abelian

Theorem

A subgroup of an abelian group is itself abelian.


Proof

Follows directly from Restriction of Commutative Operation is Commutative.

$\blacksquare$


Sources

  • 1965: J.A. Green: Sets and Groups ... (previous) ... (next): $\S 5.2$. Subgroups: Example $89$
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