Subspace of Subspace is Subspace

Theorem

Let $T = \struct{S, \tau}$ be a topological space.

Let $H \subseteq S$ be a non-empty subset of $S$ and $\tau_H$ be the subspace topology on $H$.

Let $K \subseteq S$ be a non-empty subset of $S$.


Then the subspace topology on $K$ induced by $\tau$ equals the subspace topology on $K$ induced by $\tau_H$.


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Proof

Let $\tau_K$ be the subspace topology on $K$ induced by $\tau$.

Let $\tau'_K$ be the subspace topology on $K$ induced by $\tau_H$.

Then

\(\ds V \in \tau'_K\) \(\leadstoandfrom\) \(\ds \exists U' \in \tau_H : V = U' \cap K\) Definition of Subspace Topology $\tau'_K$
\(\ds \) \(\leadstoandfrom\) \(\ds \exists U \in \tau : V = \paren {U \cap H} \cap K\) Definition of Subspace Topology $\tau_H$
\(\ds \) \(\leadstoandfrom\) \(\ds \exists U \in \tau : V = U \cap \paren {H \cap K}\) Intersection is Associative
\(\ds \) \(\leadstoandfrom\) \(\ds \exists U \in \tau : V = U \cap K\) Intersection with Subset is Subset
\(\ds \) \(\leadstoandfrom\) \(\ds V \in \tau_K\) Definition of Subspace Topology $\tau_K$

$\blacksquare$


Sources

  • 2011: John M. Lee: Introduction to Topological Manifolds (2nd ed.) ... (previous) ... (next): $\S 3$: New Spaces From Old: Subspaces